__GSA CSS
2020__

__GSA CSS 2020__

**Blood Groups of
inhabitants of a village were checked. It was found that 600 people possessed
blood group A, 650 possessed blood group B, 550 had blood group AB and 200 have
blood group O. **

**(i)
****Calculate
the probability of having blood group B. **

**(ii)
****Calculate
the probability of having blood group O.**

SOLUTION:

Blood
Group A = 600

Blood
Group B = 650

Blood
Group AB = 550

Blood
Group O = 200

Total Number = 2000

Probability
= n(blood group)/total number

Thus;

Probability
of B = 650/2000 = 0.325

Similarly,

Probability
of O = 200/2000 = 0.1

**A group of 50 men can
construct 20 kilometer road in 40 days. How long will 70 men take to complete
same length of road?**

**Solution:**

** Men Days**

50 40

70 x

Thus:

x/40 = 50/70

x = 2000/70 = 28.57

Hence, 70 men will take 28.57 days.

**Zahid left a property
worth Rs 1750,000/. His family had to pay off a debt of Rs 150,000/. The rest
of money was distributed between a son and a daughter. How much did each child
receive if share of a son was double than that of a daughter?**

Solution:

Property
left by Zahid = 1750,000

Debt = 150,000

Remaining
Amount = 1600,000

Dividing
the remaining amount by 3 = 1600,000/3 = 533,333.333

As
son’s share is double, so:

Son’s
share = 2(533,333.333) = 1066,666.67

Daughter’s
share = 533,333.333

**Tariq can do a tailoring job in 6 hours. Sajid does the same job in 4
hours. Irfan does it in 8 hours. Tariq and Sajid start doing the work. Sajid
leaves after two hours and Irfan replaces him. How long would it take to
complete the work?**

**Solution:**

** **Tariq does job
= 6 hours

Sajid
does job = 4 hrs

Irfan
does job = 8 hrs

Together, Tariq and Sajid do job
in;

1/t
= 1/6 + ¼

1/t
= 5/12

T
= 12/5 = 2.4 hrs

Together, Tariq and Irfan do job
in;

1/t
= 1/6 + 1/8

1/t
= 7/24

T
= 24/7 = 3.42 hrs

Work completed by Tariq &
Sajid in two hours;

=
100 * 2/2.4

=
83.33 %

The remaining work is = 100 – 83.33
= 16.66 %

Time taken by Tariq and Irfan to
complete the remaining work will be;

=
3.42 * 16.66/100

=
0.569

Hence, the total time taken in
completing the work is;

2
+ 0.569 = 2.569 hrs

__GSA CSS
2019__

__GSA CSS 2019__

**Moiz was trying to
sleep at one night but there was too much noise around him. His clock ticked
every 5 second; a tap was dipping every 7 second and a pet dog snored every 12
second. He noticed on his clock that all three things happened together on the
stroke of mid night. Find after how many seconds all three things happened
together again?**

Solution:

Clocked
ticked every 5 sec.

Tap
dipped every 7 sec.

Dog
snored every 12 sec.

To find out the second when all
three things happened together, simply take L.C.M

By taking L.C.M of 5, 7, 12, we
will get 420.

Thus, all three things happened
together after 420 seconds.

**The cost for hiring a
car for 2 days in 2018 was Rs 264 which was 20% more than in 2013. What was the
cost for hiring a car for 2 days in 2013?**

Solution:

Let the
cost in 2013 = x

As given in 2018;

X +
20%(x) = 264

X +
20x/100 = 264

120x/100=
264

X =
26400/120

X = 220

Thus, in 2013, the cost for hiring a car for two days was Rs
220.

**Moiz and Mair share a
lottery win of Rs 2000 in the ratio 1:4. Moiz then share his part between
himself, his wife and their son in the ratio 4:5:1. How much more does his wife
get over their son?**

Solution:

Amount
= 2000

Ratio 1 : 4

(Sum 1
+ 4= 5)

Moiz’ share is 2000*1/5 = 400 rupees.

Now, the distribution
ratio among himself, wife and son is;

4 : 5 :
1

(sum =
10)

Share of wife = 400*5/10 = 200 rupees.

Similarly, share of son = 400*1/10 = 40 rupees.

Thus,

200 – 40 = 160 rupees.

Hence, Moiz’ wife gets 160 rupees more than their son.

**A farmer keeps hens
and rabbits on his farm. One day, he counted a total of 70 heads and 196 legs.
How many more hens than rabbits does he have?**

**Solution:**

** **Let hens be ‘x’ &
rabbits be ‘y’

As given;

1x + 1y
= 70 - (i) (for heads)

2x + 4y
= 196 - (ii) (for legs)

Multiplying equation (i) by 2, we get

2x + 2y
= 140 – (iii)

By subtracting eq (iii) from (ii), we will get

2y = 56

y =
28 (thus,
there are 28 rabbits)

Putting y =28 in eq (i)

x + 28
= 70

x = 70
– 28

x = 42 (hens are 42)

Thus, the farmer has 14 more hens than rabbits.

**Each packet of washing powder carries a token and 4 tokens can be
exchanged for free packet. How many free packets will I receive if I buy 64
packets?**

Solution:

64
packets = 64 tokens

64/4
= 16 Free Packets

Moreover, 16/4 = 4 More Free
Packets

Yet, 4/4 = 1 More Free Packet

Adding all the free packets, we
get;

16 + 4 + 1 = 21 Free Packets

__GSA CSS
2018__

__GSA CSS 2018__

**It takes 3 liters of
paint to cover an area of 24 square meters. What percentage increase in the
quantity of paint would be required to cover an area of 50.4 square meters?**

Solution:

3
liters of paint covers 24 square meters

Hence, 1 liter of
paint would cover = 24/3 = 8 square meters

So, the paint required to cover an area of 50.4 square
meters would be;

50.4/8
= 6.3 liters

Increase in paint = 6.3 – 3 = 3.3 liters

In order to find out the percentage increase;

100*increase/original
value = 100*3.3/3 = 110 %

**Tahir started a
business with a capital of Rs 15,000. After 5 months Umar also joined him with
an investment of Rs 30,000. At the start of 9 ^{th} month, Usman joined
them by investing Rs 45,000. At the end of the year they earned a profit of Rs
406,000. Find the share of each one.**

Solution:

For finding investments, we would multiply capital and months
respectively.

Tahir invested 15000 for 12 months.

So, 15000*12 = 180000

Umar invested 30,000 for 7 months.

So,
30,000*7 =210000

Usman invested 45000 for 4 months.

So,
45000*4 = 180000

Now, we will find ratio to divide profit.

Ratio of their investments is;

180000
: 210000 : 180000

18 : 21
: 18

6 : 7 :
6

Sum of ratios = 6 + 7 + 6 = 19

Total earned profit is = 406000

Tahir’s share = 406000*6/19 = 128210.5

Umar’s share = 406000*7/19 = 149579

Usman’s share = 406000*6/19 = 128210.5

**A man left his
property of Rs 640,000. A debt of 40,000 was due to him and Rs 5,000 was spent
on his burial. Distribute the amount between his widow, one daughter and two
sons according to the Islamic law.**

**Solution:**

Man left =
640000

Debt amount
= 40000

Amount spent
on burial = 5000

Net Amount;

640000 –
40000 – 5000 = 595000

Now, widow’s share is 1/8 according to Islamic law.

Hence, 595000*1/8 = 74375 rupees

Remaining amount is, 595000 – 74375 = 520625

As per Islamic law, the daughter’s share is equal to half of the
son’s share.

son : son :
daughter

** **2 : 2 : 1

(sum of
ratio = 5)

Hence, each son’s share:

520625*2/5 =
208250 rupees.

And, daughter’s share is;

520625*1/5 =
104125 rupees.

**Verification:**

widow’s
share +** **son’s share + son’s share +
daughter’s share = total amount left

74375 + 208250 + 208250 + 104125 = 595000

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